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5.5=3x^2-x
We move all terms to the left:
5.5-(3x^2-x)=0
We get rid of parentheses
-3x^2+x+5.5=0
a = -3; b = 1; c = +5.5;
Δ = b2-4ac
Δ = 12-4·(-3)·5.5
Δ = 67
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{67}}{2*-3}=\frac{-1-\sqrt{67}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{67}}{2*-3}=\frac{-1+\sqrt{67}}{-6} $
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